A spring has an unstretched length of 13 cm. When an77 g ball is hung from it, the length increases by 7.0 cm. Then the ball is pulled down another 7.0 cm and released.

**What is the spring constant of the spring?**

The force of gravity on the ball = the force on the spring

Known Variable:

M(mass): 77 g or .077 kg

g(gravity) = g

ΔL = .07 m

ΔL= Mg/k

solve for K:

K=Mg/ΔL

K= (.071) x (9.8)/.07 m

= 10.78 or

11 N/m

**What is the period of the oscillation?**

**f=**1/2π√(k/m)

= 1/2π√(10.48 /.071 kg)

=.53 s

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