1/freqAn air-track glider attached to a spring oscillates between the 15.0  mark and the 55.0 cm mark on the track. The glider completes 15.0 oscillations in 37.0 .

What are the

(a) period

= 1/frequency

= 1/.405

= 2.5 seconds

(b) frequency

= oscillations / time

= 15/37= .41 Hz

(c) amplitude

amplitude = 1/2 of the difference of oscillation marks

= 1/2(55-15) = 20cm

(d) maximum speed of the glider?

2π x frequency x amplitude = maximum speed

= 2π x .41 x 20

=51 cm/s