Period, Frequency, Amplitude, and Maximum Speed
1/freqAn air-track glider attached to a spring oscillates between the 15.0 mark and the 55.0 cm mark on the track. The glider completes 15.0 oscillations in 37.0 .
What are the
= 2.5 seconds
= oscillations / time
= 15/37= .41 Hz
amplitude = 1/2 of the difference of oscillation marks
= 1/2(55-15) = 20cm
(d) maximum speed of the glider?
2π x frequency x amplitude = maximum speed
= 2π x .41 x 20