**An object’s moment of inertia is 2.2 kg m**^{2}**. Its angular velocity is increasing at the rate of 3.6 rad.sec**^{2}**.**

**What is the torque on the object?**

**Known Variables:**

**Angular acceleration (****α)**=3.6 rad/s^{2}**
Moment of inertia (I)=**2.2 kg m

^{2}

**Torque (τ)**= α x I

With this equation,

**τ**=2.2 kg m^{2} x 3.6 rad/s^{2}

**τ**=7.92 N*m

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