What is the Speed of the Ball?

A 71 kg baseball player jumps straight up to catch a line drive.

If the 140 g ball is moving horizontally at 29 m/s, and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball?

Known variables:

(player) m1= 71 kg

(ball) m2 = 140 g or .140 kg

v1= 0

v2= 29 m/s

m1v1+m2v2=(m1+m2)v

(71)v1 + (.140 x 29)  = (71 + .140)
(71*0)+(.140*29)=(71+.140)v
4.06=71.14v

v=.057 m/s

conversion:

.052*100

v= 5.2 cm/s