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Comments ( 2 )
2<1<3
"if m1 and m2 are the two mass which are separated by distanceR by fixed mass less rod , are rotated on the axispassing through mid point
I = m1 ( R/2 )2 + m2 ( R/2)2
for 1 we have
I = m ( R/2 ) 2 +m ( R/2 ) 2 = 1/2 mR2
for 2 we have
I = 2m ( R/4 ) 2 + m ( R/4 ) 2 =3 /16 m R2
for 3 we have
I= m/2 ( R ) 2 + m/2 ( R) 2 = mR2
so we have the order 2<1<3"
In the response answer, for I3, is that MR(2) or MR^2