**How much energy can be stored in a spring with k = 490 N/m if the maximum possible stretch is 20 cm?**

**Known variables:**

**k=490**

**x= 20cm or**

*.2m*

**Kinetic Energy Equation**

**K.E=**1/2kx^{2}**Once you know your variables and your equation, just plug it in.**

**K.E**= .5 x (490) x (.2)

^{2}

**K.E**= 9.8 J

## Leave a Reply