What is the Takeoff and Horizontal Speed?

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 9.0 m from the takeoff point.

If the kangaroo leaves the ground at a 20° angle, what is its takeoff speed ?

R (range) = v₀² sin2(θ) / g
9.0 m = v₀² sin2(20) / 9.81
v₀ = 11.7 m/s (takeoff speed)
= 12 m/s

What is its horizontal speed?
Horizontal speed
V_x =v₀ cos(20)
12cos(20)
= 11.27
=11 m/s