A man standing on very slick ice fires a rifle horizontally. The mass of the man together with the rifle is 70 kg, and the mass of the bullet is 10 g.
If the bullet leaves the muzzle at a speed of 500 m/s, what is the final speed of the man?
Known variables:
(man) mass(m1): 70 kg
(bullet)mass(m2): 10 g or .01 kg
(bullet)velocity(v2): 500 m/s
m1 v1 = m2 v2
70 kg x v1 = .01 kg x 500 m/s
70 v1 = 5
v1 = 5/70
v1 = .071 m/s or
7.1 x 10-2 m/s
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