A 504 g mass oscillates with an amplitude of 13.0 cm on a spring whose spring constant is 25.0 N/m.
Known variables:
m = .504kg
k= 25 N/m
1/2π √25N/m / .504kg)
= .89 s
Determine the maximum speed.
F = 1/.89
=1.12
Vmax= 2π fA
2 x π x 1.12 x .13
=.9148
=.916
Determine the total energy.
=1/2 kA2
=1/2 (25) (.13)2
= .21 J
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